Representation error refers to fact that some (most, actually) decimal fractions cannot be represented exactly as binary (base 2) fractions. This is the chief reason why Python (or Perl, C, C++, Java, Fortran, and many others) often won’t display the exact decimal number you expect:
>>> 0.1
0.10000000000000001Why is that? 1/10 is not exactly representable as a binary fraction. Almost all machines today use floating point arithmetic, and almost all platforms map Python floats to “double precision”. doubles contain 53 bits of precision, so on input the computer strives to convert 0.1 to the closest fraction it can of the form J/2**N where J is an integer containing exactly 53 bits. Rewriting
1 / 10 ~= J / (2**N)as J ~= 2**N / 10 and recalling that J has exactly 53 bits (is >= 2**52 but < 2**53), the best value for N is 56: >>> 2**524503599627370496L>>> 2**539007199254740992L>>> 2**56/107205759403792793L That is, 56 is the only value for N that leaves J with exactly 53 bits. The best possible value for J is then that quotient rounded: >>> q, r = divmod(2**56, 10)>>> r6L Since the remainder is more than half of 10, the best approximation is obtained by rounding up: >>> q+17205759403792794L Therefore the best possible approximation to 1/10 in double precision is that over 2**56, or 7205759403792794 / 72057594037927936. Note that since we rounded up, this is actually a little bit larger than 1/10; if we had not rounded up, the quotient would have been a little bit smaller than 1/10. But in no case can it be exactly 1/10! So the computer never “sees” 1/10: what it sees is the exact fraction given above, the best double approximation it can get: >>> .1 * 2**567205759403792794.0 .If we multiply that fraction by 10**30, we can see the (truncated) value of its 30 most significant decimal digits: >>> 7205759403792794 * 10**30 / 2**56100000000000000005551115123125L meaning that the exact number stored in the computer is approximately equal to the decimal value 0.100000000000000005551115123125. Rounding that to 17 significant digits gives the 0.10000000000000001 that Python displays (well, will display on any conforming platform that does best-possible input and output conversions in its C library
Be Orginal man,instead of pasting from Net!!